NCERT Class 12 Physics Part-2 Solutions | Content | English Medium

  1. Reflection is governed by the equation –i = –r¢ and refraction by the

Snell’s law, sini/sinr = n, where the incident ray, reflected ray, refracted

ray and normal lie in the same plane. Angles of incidence, reflection

and refraction are i, r ¢ and r, respectively.

Ans

  1. The critical angle of incidence i

c

for a ray incident from a denser to rarer

medium, is that angle for which the angle of refraction is 90°. For

i > i

c

, total internal reflection occurs. Multiple internal reflections in

diamond (i

c

@ 24.4°), totally reflecting prisms and mirage, are some

examples of total internal reflection. Optical fibres consist of glass

fibres coated with a thin layer of material of lower refractive index.

Light incident at an angle at one end comes out at the other, after

multiple internal reflections, even if the fibre is bent.

FIGURE 9.26 Schematic diagram of a reflecting telescope (Cassegrain).

the telescope tube. One must have an eyepiece and the observer right

there, obstructing some light (depending on the size of the observer cage).

This is what is done in the very large 200 inch (~5.08 m) diameters, Mt.

Palomar telescope, California. The viewer sits near the focal point of the

mirror, in a small cage. Another solution to the problem is to deflect the

light being focussed by another mirror. One such arrangement using a

convex secondary mirror to focus the incident light, which now passes

through a hole in the objective primary mirror, is shown in Fig. 9.26.

This is known as a Cassegrain telescope, after its inventor. It has the

advantages of a large focal length in a short telescope. The largest telescope

in India is in Kavalur, Tamil Nadu. It is a 2.34 m diameter reflecting

telescope (Cassegrain). It was ground, polished, set up, and is being used

by the Indian Institute of Astrophysics, Bangalore. The largest reflecting

telescopes in the world are the pair of Keck telescopes in Hawaii, USA,

with a reflector of 10 metre in diameter.

Ans

  1. Cartesian sign convention: Distances measured in the same direction

as the incident light are positive; those measured in the opposite

direction are negative. All distances are measured from the pole/optic

centre of the mirror/lens on the principal axis. The heights measured

upwards above x-axis and normal to the principal axis of the mirror/

lens are taken as positive. The heights measured downwards are taken

as negative.

Ans

  1. Mirror equation:

1 1 1

v u f

  • =

where u and v are object and image distances, respectively and f is the

focal length of the mirror. f is (approximately) half the radius of

curvature R. f is negative for concave mirror; f is positive for a convex

mirror.

Ans

  1. For a prism of the angle A, of refractive index n2

placed in a medium

of refractive index n1

,

n

n

n

A D

A

m

21

2

1

2

2

= =

( ) + 

( )

sin /

sin /

where Dm

is the angle of minimum deviation.

Ans

  1. For refraction through a spherical interface (from medium 1 to 2 of

refractive index n1

and n2

, respectively)

n n n n 2 1 2 1

v u R

− =

Thin lens formula

1 1 1

v u f

− =

Lens maker’s formula

1 2 1 1 1

1 1 2 f

n n

n R R

=

( − )

R1

and R2

are the radii of curvature of the lens surfaces. f is positive

for a converging lens; f is negative for a diverging lens. The power of a

lens P = 1/f.

The SI unit for power of a lens is dioptre (D): 1 D = 1 m–1

.

If several thin lenses of focal length f

1

, f

2

, f

3

,.. are in contact, the

effective focal length of their combination, is given by

1 2 3

1 1 1 1

f f f f

= + + + …

The total power of a combination of several lenses is

P = P1

  • P2
  • P3

Ans

  1. Dispersion is the splitting of light into its constituent colour.

Ans

  1. Magnifying power m of a simple microscope is given by m = 1 + (D/f),

where D = 25 cm is the least distance of distinct vision and f is the

focal length of the convex lens. If the image is at infinity, m = D/f. For

a compound microscope, the magnifying power is given by m = me

× m0

where me

= 1 + (D/f

e

), is the magnification due to the eyepiece and mo

is the magnification produced by the objective. Approximately,

o e

L D

m

f f

= ×

where f

o

and f

e

are the focal lengths of the objective and eyepiece,

respectively, and L is the distance between their focal points.

Ans

  1. Magnifying power m of a telescope is the ratio of the angle b subtended

at the eye by the image to the angle a subtended at the eye by the

object.

o

e

f

m

f

β

α

= =

where f

0

and f

e

are the focal lengths of the objective and eyepiece,

respectively.

Ans

  1. The laws of reflection and refraction are true for all surfaces and

pairs of media at the point of the incidence.

Ans

  1. The real image of an object placed between f and 2f from a convex lens

can be seen on a screen placed at the image location. If the screen is

removed, is the image still there? This question puzzles many, because

it is difficult to reconcile ourselves with an image suspended in air

without a screen. But the image does exist. Rays from a given point

on the object are converging to an image point in space and diverging

away. The screen simply diffuses these rays, some of which reach our

eye and we see the image. This can be seen by the images formed in

air during a laser show.

Ans

  1. Image formation needs regular reflection/refraction. In principle, all

rays from a given point should reach the same image point. This is

why you do not see your image by an irregular reflecting object, say

the page of a book.

Ans

  1. Thick lenses give coloured images due to dispersion. The variety in

colour of objects we see around us is due to the constituent colours

of the light incident on them. A monochromatic light may produce an

entirely different perception about the colours on an object as seen in

white light.

Ans

  1. For a simple microscope, the angular size of the object equals the

angular size of the image. Yet it offers magnification because we can

keep the small object much closer to the eye than 25 cm and hence

have it subtend a large angle. The image is at 25 cm which we can see.

Without the microscope, you would need to keep the small object at

25 cm which would subtend a very small angle.

Ans